Base | Representation |
---|---|
bin | 10010010001011011… |
… | …101001011101010011 |
3 | 1212122100010210000021 |
4 | 102101123221131103 |
5 | 310140133010303 |
6 | 13002504404311 |
7 | 1263124442404 |
oct | 222133513523 |
9 | 55570123007 |
10 | 19619813203 |
11 | 8358967061 |
12 | 3976776697 |
13 | 1b089b2733 |
14 | d419db9ab |
15 | 79c6bcebd |
hex | 4916e9753 |
19619813203 has 12 divisors (see below), whose sum is σ = 20847878800. Its totient is φ = 18460328832.
The previous prime is 19619813201. The next prime is 19619813209. The reversal of 19619813203 is 30231891691.
It is not a de Polignac number, because 19619813203 - 21 = 19619813201 is a prime.
It is a super-2 number, since 2×196198132032 (a number of 21 digits) contains 22 as substring.
It is a hoax number, since the sum of its digits (43) coincides with the sum of the digits of its distinct prime factors.
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 19619813203.
It is not an unprimeable number, because it can be changed into a prime (19619813201) by changing a digit.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 1270573 + ... + 1285921.
Almost surely, 219619813203 is an apocalyptic number.
19619813203 is a deficient number, since it is larger than the sum of its proper divisors (1228065597).
19619813203 is a wasteful number, since it uses less digits than its factorization.
19619813203 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 19806 (or 19789 counting only the distinct ones).
The product of its (nonzero) digits is 69984, while the sum is 43.
The spelling of 19619813203 in words is "nineteen billion, six hundred nineteen million, eight hundred thirteen thousand, two hundred three".
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