Base | Representation |
---|---|
bin | 1000111110111010100110… |
… | …00011100101100001010001 |
3 | 2120221110101121022000212002 |
4 | 10133131103003211201101 |
5 | 10042122041144341340 |
6 | 110002501034443345 |
7 | 4106114150631365 |
oct | 437352303454121 |
9 | 76843347260762 |
10 | 19753948043345 |
11 | 632666976022a |
12 | 2270545293555 |
13 | b03a35154689 |
14 | 4c414bd172a5 |
15 | 243ca397c715 |
hex | 11f7530e5851 |
19753948043345 has 4 divisors (see below), whose sum is σ = 23704737652020. Its totient is φ = 15803158434672.
The previous prime is 19753948043329. The next prime is 19753948043443. The reversal of 19753948043345 is 54334084935791.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 2501455396801 + 17252492646544 = 1581599^2 + 4153612^2 .
It is a cyclic number.
It is not a de Polignac number, because 19753948043345 - 24 = 19753948043329 is a prime.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1975394804330 + ... + 1975394804339.
It is an arithmetic number, because the mean of its divisors is an integer number (5926184413005).
Almost surely, 219753948043345 is an apocalyptic number.
It is an amenable number.
19753948043345 is a deficient number, since it is larger than the sum of its proper divisors (3950789608675).
19753948043345 is an equidigital number, since it uses as much as digits as its factorization.
19753948043345 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3950789608674.
The product of its (nonzero) digits is 195955200, while the sum is 65.
The spelling of 19753948043345 in words is "nineteen trillion, seven hundred fifty-three billion, nine hundred forty-eight million, forty-three thousand, three hundred forty-five".
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