Base | Representation |
---|---|
bin | 101101000000011100001010… |
… | …011101111001001111011111 |
3 | 221221212002202112212100211222 |
4 | 231000130022131321033133 |
5 | 201421041344321121201 |
6 | 1540553241432403555 |
7 | 56456601355525535 |
oct | 5500341235711737 |
9 | 857762675770758 |
10 | 197942333379551 |
11 | 58085965935062 |
12 | 1a24a672b465bb |
13 | 865ab6082bab7 |
14 | 36c466255c155 |
15 | 17d3e0362591b |
hex | b4070a7793df |
197942333379551 has 4 divisors (see below), whose sum is σ = 197943694729872. Its totient is φ = 197940972029232.
The previous prime is 197942333379541. The next prime is 197942333379673. The reversal of 197942333379551 is 155973333249791.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-197942333379551 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (197942333379521) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 680457035 + ... + 680747868.
It is an arithmetic number, because the mean of its divisors is an integer number (49485923682468).
Almost surely, 2197942333379551 is an apocalyptic number.
197942333379551 is a deficient number, since it is larger than the sum of its proper divisors (1361350321).
197942333379551 is a wasteful number, since it uses less digits than its factorization.
197942333379551 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1361350320.
The product of its digits is 578680200, while the sum is 71.
The spelling of 197942333379551 in words is "one hundred ninety-seven trillion, nine hundred forty-two billion, three hundred thirty-three million, three hundred seventy-nine thousand, five hundred fifty-one".
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