Base | Representation |
---|---|
bin | 11100110100011000000… |
… | …101101011100110011001 |
3 | 21000022201101000011010222 |
4 | 130310120011223212121 |
5 | 224421311310102240 |
6 | 4113435331245425 |
7 | 263035522546655 |
oct | 34643005534631 |
9 | 7008641004128 |
10 | 1980384065945 |
11 | 6a39701a423a |
12 | 27b98a749875 |
13 | 11499860c4bc |
14 | 6bbcb5c1a65 |
15 | 367aad28eb5 |
hex | 1cd1816b999 |
1980384065945 has 4 divisors (see below), whose sum is σ = 2376460879140. Its totient is φ = 1584307252752.
The previous prime is 1980384065917. The next prime is 1980384065963. The reversal of 1980384065945 is 5495604830891.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 735472614409 + 1244911451536 = 857597^2 + 1115756^2 .
It is a cyclic number.
It is not a de Polignac number, because 1980384065945 - 214 = 1980384049561 is a prime.
It is a Curzon number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 198038406590 + ... + 198038406599.
It is an arithmetic number, because the mean of its divisors is an integer number (594115219785).
Almost surely, 21980384065945 is an apocalyptic number.
It is an amenable number.
1980384065945 is a deficient number, since it is larger than the sum of its proper divisors (396076813195).
1980384065945 is an equidigital number, since it uses as much as digits as its factorization.
1980384065945 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 396076813194.
The product of its (nonzero) digits is 37324800, while the sum is 62.
The spelling of 1980384065945 in words is "one trillion, nine hundred eighty billion, three hundred eighty-four million, sixty-five thousand, nine hundred forty-five".
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