Base | Representation |
---|---|
bin | 1011100001110010101… |
… | …0111110001001000001 |
3 | 200221012102010011000102 |
4 | 2320130222332021001 |
5 | 11221101134202431 |
6 | 230552132332145 |
7 | 20210565106634 |
oct | 2703452761101 |
9 | 627172104012 |
10 | 198049522241 |
11 | 76aa087940a |
12 | 32472474055 |
13 | 158a31c391c |
14 | 982b037c1b |
15 | 52420e4dcb |
hex | 2e1cabe241 |
198049522241 has 2 divisors, whose sum is σ = 198049522242. Its totient is φ = 198049522240.
The previous prime is 198049522189. The next prime is 198049522243. The reversal of 198049522241 is 142225940891.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 185140017841 + 12909504400 = 430279^2 + 113620^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-198049522241 is a prime.
It is a super-2 number, since 2×1980495222412 (a number of 23 digits) contains 22 as substring.
Together with 198049522243, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (198049522243) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 99024761120 + 99024761121.
It is an arithmetic number, because the mean of its divisors is an integer number (99024761121).
Almost surely, 2198049522241 is an apocalyptic number.
It is an amenable number.
198049522241 is a deficient number, since it is larger than the sum of its proper divisors (1).
198049522241 is an equidigital number, since it uses as much as digits as its factorization.
198049522241 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 414720, while the sum is 47.
The spelling of 198049522241 in words is "one hundred ninety-eight billion, forty-nine million, five hundred twenty-two thousand, two hundred forty-one".
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