Base | Representation |
---|---|
bin | 1001000000100011101011… |
… | …11101001001001011000011 |
3 | 2121010212000121122111011001 |
4 | 10200101311331021023003 |
5 | 10044033113220204104 |
6 | 110044431341032431 |
7 | 4113152250522211 |
oct | 440216575111303 |
9 | 77125017574131 |
10 | 19810368131779 |
11 | 634859139a795 |
12 | 227b470255717 |
13 | b091570161a4 |
14 | 4c6b81169cb1 |
15 | 2454a6c8aaa4 |
hex | 120475f492c3 |
19810368131779 has 2 divisors, whose sum is σ = 19810368131780. Its totient is φ = 19810368131778.
The previous prime is 19810368131767. The next prime is 19810368131797. The reversal of 19810368131779 is 97713186301891.
It is a happy number.
Together with next prime (19810368131797) it forms an Ormiston pair, because they use the same digits, order apart.
It is a weak prime.
It is an emirp because it is prime and its reverse (97713186301891) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 19810368131779 - 229 = 19809831260867 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 19810368131779.
It is not a weakly prime, because it can be changed into another prime (19810368131579) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 9905184065889 + 9905184065890.
It is an arithmetic number, because the mean of its divisors is an integer number (9905184065890).
Almost surely, 219810368131779 is an apocalyptic number.
19810368131779 is a deficient number, since it is larger than the sum of its proper divisors (1).
19810368131779 is an equidigital number, since it uses as much as digits as its factorization.
19810368131779 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 13716864, while the sum is 64.
The spelling of 19810368131779 in words is "nineteen trillion, eight hundred ten billion, three hundred sixty-eight million, one hundred thirty-one thousand, seven hundred seventy-nine".
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