Base | Representation |
---|---|
bin | 10111100111100… |
… | …10011111111111 |
3 | 111210210211011222 |
4 | 23303302133333 |
5 | 401210004232 |
6 | 31354303555 |
7 | 4624016363 |
oct | 1363623777 |
9 | 453724158 |
10 | 198125567 |
11 | a1922742 |
12 | 56427bbb |
13 | 3207c083 |
14 | 1c4552a3 |
15 | 125d8d12 |
hex | bcf27ff |
198125567 has 2 divisors, whose sum is σ = 198125568. Its totient is φ = 198125566.
The previous prime is 198125563. The next prime is 198125573. The reversal of 198125567 is 765521891.
It is a weak prime.
It is an emirp because it is prime and its reverse (765521891) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 198125567 - 22 = 198125563 is a prime.
It is a super-3 number, since 3×1981255673 (a number of 26 digits) contains 333 as substring.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (198125563) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 99062783 + 99062784.
It is an arithmetic number, because the mean of its divisors is an integer number (99062784).
Almost surely, 2198125567 is an apocalyptic number.
198125567 is a deficient number, since it is larger than the sum of its proper divisors (1).
198125567 is an equidigital number, since it uses as much as digits as its factorization.
198125567 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 151200, while the sum is 44.
The square root of 198125567 is about 14075.7084013559. The cubic root of 198125567 is about 582.9708517722.
The spelling of 198125567 in words is "one hundred ninety-eight million, one hundred twenty-five thousand, five hundred sixty-seven".
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