1981335003 has 4 divisors (see below), whose sum is σ = 2641780008. Its totient is φ = 1320890000.

The previous prime is 1981334981. The next prime is 1981335007. The reversal of 1981335003 is 3005331891.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1981335003 - 2⁶ = 1981334939 is a prime.

It is a super-3 number, since 3×1981335003³ (a number of 29 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is not an unprimeable number, because it can be changed into a prime (1981335007) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 330222498 + ... + 330222503.

It is an arithmetic number, because the mean of its divisors is an integer number (660445002).

Almost surely, 2^1981335003 is an apocalyptic number.

1981335003 is a deficient number, since it is larger than the sum of its proper divisors (660445005).

1981335003 is an equidigital number, since it uses as much as digits as its factorization.

1981335003 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 660445004.

The product of its (nonzero) digits is 9720, while the sum is 33.

The square root of 1981335003 is about 44512.1893754958. The cubic root of 1981335003 is about 1255.9893899042.

Adding to 1981335003 its reverse (3005331891), we get a palindrome (4986666894).

The spelling of 1981335003 in words is "one billion, nine hundred eighty-one million, three hundred thirty-five thousand, three".