Base | Representation |
---|---|
bin | 10111100111101… |
… | …01011010011001 |
3 | 111210211102112211 |
4 | 23303311122121 |
5 | 401210344442 |
6 | 31354435121 |
7 | 4624066225 |
oct | 1363653231 |
9 | 453742484 |
10 | 198137497 |
11 | a19306a8 |
12 | 56432aa1 |
13 | 3208462c |
14 | 1c459785 |
15 | 125dc617 |
hex | bcf5699 |
198137497 has 2 divisors, whose sum is σ = 198137498. Its totient is φ = 198137496.
The previous prime is 198137473. The next prime is 198137501. The reversal of 198137497 is 794731891.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 198133776 + 3721 = 14076^2 + 61^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-198137497 is a prime.
It is a super-3 number, since 3×1981374973 (a number of 26 digits) contains 333 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 198137497.
It is not a weakly prime, because it can be changed into another prime (198137437) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 99068748 + 99068749.
It is an arithmetic number, because the mean of its divisors is an integer number (99068749).
Almost surely, 2198137497 is an apocalyptic number.
It is an amenable number.
198137497 is a deficient number, since it is larger than the sum of its proper divisors (1).
198137497 is an equidigital number, since it uses as much as digits as its factorization.
198137497 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 381024, while the sum is 49.
The square root of 198137497 is about 14076.1321747133. The cubic root of 198137497 is about 582.9825526055.
The spelling of 198137497 in words is "one hundred ninety-eight million, one hundred thirty-seven thousand, four hundred ninety-seven".
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