Base | Representation |
---|---|
bin | 11100110101010100001… |
… | …011010101000111111011 |
3 | 21000102022121221122020201 |
4 | 130311110023111013323 |
5 | 224430342344222312 |
6 | 4114123342503031 |
7 | 263102513433103 |
oct | 34652413250773 |
9 | 7012277848221 |
10 | 1981392179707 |
11 | 6a433825a006 |
12 | 280010294a77 |
13 | 114ac942a815 |
14 | 6bc85442203 |
15 | 368195ae557 |
hex | 1cd542d51fb |
1981392179707 has 2 divisors, whose sum is σ = 1981392179708. Its totient is φ = 1981392179706.
The previous prime is 1981392179681. The next prime is 1981392179717. The reversal of 1981392179707 is 7079712931891.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1981392179707 is a prime.
It is a super-3 number, since 3×19813921797073 (a number of 38 digits) contains 333 as substring.
It is not a weakly prime, because it can be changed into another prime (1981392179717) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 990696089853 + 990696089854.
It is an arithmetic number, because the mean of its divisors is an integer number (990696089854).
Almost surely, 21981392179707 is an apocalyptic number.
1981392179707 is a deficient number, since it is larger than the sum of its proper divisors (1).
1981392179707 is an equidigital number, since it uses as much as digits as its factorization.
1981392179707 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 12002256, while the sum is 64.
The spelling of 1981392179707 in words is "one trillion, nine hundred eighty-one billion, three hundred ninety-two million, one hundred seventy-nine thousand, seven hundred seven".
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