19814241349 has 4 divisors (see below), whose sum is σ = 22644847264. Its totient is φ = 16983635436.

The previous prime is 19814241347. The next prime is 19814241401. The reversal of 19814241349 is 94314241891.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 19814241349 - 2¹ = 19814241347 is a prime.

It is a super-3 number, since 3×19814241349³ (a number of 32 digits) contains 333 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 19814241299 and 19814241308.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (19814241347) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1415302947 + ... + 1415302960.

It is an arithmetic number, because the mean of its divisors is an integer number (5661211816).

Almost surely, 2^19814241349 is an apocalyptic number.

It is an amenable number.

19814241349 is a deficient number, since it is larger than the sum of its proper divisors (2830605915).

19814241349 is an equidigital number, since it uses as much as digits as its factorization.

19814241349 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2830605914.

The product of its digits is 248832, while the sum is 46.

The spelling of 19814241349 in words is "nineteen billion, eight hundred fourteen million, two hundred forty-one thousand, three hundred forty-nine".