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198155033 is a prime number
BaseRepresentation
bin10111100111110…
…01101100011001
3111210212022121022
423303321230121
5401211430113
631355052225
74624201316
oct1363715431
9453768538
10198155033
11a194289a
1256441075
133208c5cb
141c461d0d
15125e2908
hexbcf9b19

198155033 has 2 divisors, whose sum is σ = 198155034. Its totient is φ = 198155032.

The previous prime is 198154993. The next prime is 198155059. The reversal of 198155033 is 330551891.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 134745664 + 63409369 = 11608^2 + 7963^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-198155033 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 198154984 and 198155002.

It is not a weakly prime, because it can be changed into another prime (198155063) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 99077516 + 99077517.

It is an arithmetic number, because the mean of its divisors is an integer number (99077517).

Almost surely, 2198155033 is an apocalyptic number.

It is an amenable number.

198155033 is a deficient number, since it is larger than the sum of its proper divisors (1).

198155033 is an equidigital number, since it uses as much as digits as its factorization.

198155033 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 16200, while the sum is 35.

The square root of 198155033 is about 14076.7550593168. The cubic root of 198155033 is about 582.9997508990. Note that the first 3 decimals are identical.

The spelling of 198155033 in words is "one hundred ninety-eight million, one hundred fifty-five thousand, thirty-three".