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1981980000029 is a prime number
BaseRepresentation
bin11100110101110111001…
…101101011111100011101
321000110211121001000010202
4130311313031223330131
5224433043340000104
64114301541513245
7263123212014011
oct34656715537435
97013747030122
101981980000029
116a460a049127
12280155112825
13114b911506b3
146bcdd538541
1536850ec351e
hex1cd7736bf1d

1981980000029 has 2 divisors, whose sum is σ = 1981980000030. Its totient is φ = 1981980000028.

The previous prime is 1981980000001. The next prime is 1981980000037. The reversal of 1981980000029 is 9200000891891.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1925669659225 + 56310340804 = 1387685^2 + 237298^2 .

It is an emirp because it is prime and its reverse (9200000891891) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1981980000029 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1981980000089) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 990990000014 + 990990000015.

It is an arithmetic number, because the mean of its divisors is an integer number (990990000015).

Almost surely, 21981980000029 is an apocalyptic number.

It is an amenable number.

1981980000029 is a deficient number, since it is larger than the sum of its proper divisors (1).

1981980000029 is an equidigital number, since it uses as much as digits as its factorization.

1981980000029 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 93312, while the sum is 47.

The spelling of 1981980000029 in words is "one trillion, nine hundred eighty-one billion, nine hundred eighty million, twenty-nine", and thus it is an aban number.