Base | Representation |
---|---|
bin | 1011100010100110110… |
… | …0111000011101001011 |
3 | 200221202122110102102212 |
4 | 2320221230320131023 |
5 | 11222023120031201 |
6 | 231025542015335 |
7 | 20216161162511 |
oct | 2705154703513 |
9 | 627678412385 |
10 | 198268127051 |
11 | 770a3209445 |
12 | 3251371754b |
13 | 15909593297 |
14 | 984c0a04b1 |
15 | 52563c6abb |
hex | 2e29b3874b |
198268127051 has 4 divisors (see below), whose sum is σ = 209930958072. Its totient is φ = 186605296032.
The previous prime is 198268127009. The next prime is 198268127089. The reversal of 198268127051 is 150721862891.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-198268127051 is a prime.
It is a super-2 number, since 2×1982681270512 (a number of 23 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (198228127051) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5831415485 + ... + 5831415518.
It is an arithmetic number, because the mean of its divisors is an integer number (52482739518).
Almost surely, 2198268127051 is an apocalyptic number.
198268127051 is a deficient number, since it is larger than the sum of its proper divisors (11662831021).
198268127051 is a wasteful number, since it uses less digits than its factorization.
198268127051 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 11662831020.
The product of its (nonzero) digits is 483840, while the sum is 50.
The spelling of 198268127051 in words is "one hundred ninety-eight billion, two hundred sixty-eight million, one hundred twenty-seven thousand, fifty-one".
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