Base | Representation |
---|---|
bin | 1001000001010001001101… |
… | …10100011010001101001111 |
3 | 2121020012010000210112111111 |
4 | 10200220212310122031033 |
5 | 10044433142410332332 |
6 | 110103552552232451 |
7 | 4115006042206303 |
oct | 440504664321517 |
9 | 77205100715444 |
10 | 19834810245967 |
11 | 6357994322962 |
12 | 228415199b727 |
13 | b0b550aaaa52 |
14 | 4c801d3add03 |
15 | 245e379ad947 |
hex | 120a26d1a34f |
19834810245967 has 2 divisors, whose sum is σ = 19834810245968. Its totient is φ = 19834810245966.
The previous prime is 19834810245947. The next prime is 19834810246007. The reversal of 19834810245967 is 76954201843891.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 19834810245967 - 219 = 19834809721679 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (19834810245947) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 9917405122983 + 9917405122984.
It is an arithmetic number, because the mean of its divisors is an integer number (9917405122984).
It is a 1-persistent number, because it is pandigital, but 2⋅19834810245967 = 39669620491934 is not.
Almost surely, 219834810245967 is an apocalyptic number.
19834810245967 is a deficient number, since it is larger than the sum of its proper divisors (1).
19834810245967 is an equidigital number, since it uses as much as digits as its factorization.
19834810245967 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 104509440, while the sum is 67.
The spelling of 19834810245967 in words is "nineteen trillion, eight hundred thirty-four billion, eight hundred ten million, two hundred forty-five thousand, nine hundred sixty-seven".
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