Base | Representation |
---|---|
bin | 10111101001101… |
… | …00100111110011 |
3 | 111211022120200221 |
4 | 23310310213303 |
5 | 401242141103 |
6 | 31404153511 |
7 | 4626225112 |
oct | 1364644763 |
9 | 454276627 |
10 | 198396403 |
11 | a1a98177 |
12 | 56538897 |
13 | 3214542a |
14 | 1c4c5c79 |
15 | 1263e1bd |
hex | bd349f3 |
198396403 has 2 divisors, whose sum is σ = 198396404. Its totient is φ = 198396402.
The previous prime is 198396371. The next prime is 198396427. The reversal of 198396403 is 304693891.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 198396403 - 25 = 198396371 is a prime.
It is a super-2 number, since 2×1983964032 = 78722265446676818, which contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 198396403.
It is not a weakly prime, because it can be changed into another prime (198390403) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 99198201 + 99198202.
It is an arithmetic number, because the mean of its divisors is an integer number (99198202).
Almost surely, 2198396403 is an apocalyptic number.
198396403 is a deficient number, since it is larger than the sum of its proper divisors (1).
198396403 is an equidigital number, since it uses as much as digits as its factorization.
198396403 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 139968, while the sum is 43.
The square root of 198396403 is about 14085.3258038286. The cubic root of 198396403 is about 583.2363695884.
The spelling of 198396403 in words is "one hundred ninety-eight million, three hundred ninety-six thousand, four hundred three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.070 sec. • engine limits •