Base | Representation |
---|---|
bin | 10010011111010001… |
… | …111101001000110101 |
3 | 1220020112022212211122 |
4 | 102133101331020311 |
5 | 311124122402042 |
6 | 13041524313325 |
7 | 1301645343146 |
oct | 223721751065 |
9 | 56215285748 |
10 | 19852153397 |
11 | 846802874a |
12 | 3a20542845 |
13 | 1b44b80c3b |
14 | d647dbacd |
15 | 7b2cb47d2 |
hex | 49f47d235 |
19852153397 has 2 divisors, whose sum is σ = 19852153398. Its totient is φ = 19852153396.
The previous prime is 19852153331. The next prime is 19852153423. The reversal of 19852153397 is 79335125891.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 19624927921 + 227225476 = 140089^2 + 15074^2 .
It is a cyclic number.
It is not a de Polignac number, because 19852153397 - 222 = 19847959093 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (19852153897) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 9926076698 + 9926076699.
It is an arithmetic number, because the mean of its divisors is an integer number (9926076699).
Almost surely, 219852153397 is an apocalyptic number.
It is an amenable number.
19852153397 is a deficient number, since it is larger than the sum of its proper divisors (1).
19852153397 is an equidigital number, since it uses as much as digits as its factorization.
19852153397 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 2041200, while the sum is 53.
The spelling of 19852153397 in words is "nineteen billion, eight hundred fifty-two million, one hundred fifty-three thousand, three hundred ninety-seven".
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