Base | Representation |
---|---|
bin | 11100111101100111001… |
… | …111000001011101101111 |
3 | 21001021022120001202110011 |
4 | 130331213033001131233 |
5 | 230102114233140310 |
6 | 4122155415554051 |
7 | 263536351404463 |
oct | 34754717013557 |
9 | 7037276052404 |
10 | 1990301849455 |
11 | 6a809a563837 |
12 | 28189808b927 |
13 | 1158b927175a |
14 | 6c48c8624a3 |
15 | 36b8b89678a |
hex | 1cf673c176f |
1990301849455 has 16 divisors (see below), whose sum is σ = 2410372578240. Its totient is φ = 1577569105152.
The previous prime is 1990301849387. The next prime is 1990301849479. The reversal of 1990301849455 is 5549481030991.
It is a cyclic number.
It is not a de Polignac number, because 1990301849455 - 213 = 1990301841263 is a prime.
It is a super-2 number, since 2×19903018494552 (a number of 25 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 1990301849455.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 16670382 + ... + 16789348.
It is an arithmetic number, because the mean of its divisors is an integer number (150648286140).
Almost surely, 21990301849455 is an apocalyptic number.
1990301849455 is a deficient number, since it is larger than the sum of its proper divisors (420070728785).
1990301849455 is a wasteful number, since it uses less digits than its factorization.
1990301849455 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 149778.
The product of its (nonzero) digits is 6998400, while the sum is 58.
The spelling of 1990301849455 in words is "one trillion, nine hundred ninety billion, three hundred one million, eight hundred forty-nine thousand, four hundred fifty-five".
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