Base | Representation |
---|---|
bin | 1011100110000100111… |
… | …0000000101011111111 |
3 | 201001011120010001001012 |
4 | 2321201032000223333 |
5 | 11230430041332044 |
6 | 231302213505435 |
7 | 20251231211012 |
oct | 2714116005377 |
9 | 631146101035 |
10 | 199199558399 |
11 | 77530a59616 |
12 | 3273364227b |
13 | 15a275432aa |
14 | 98d9a7d379 |
15 | 52ad06159e |
hex | 2e61380aff |
199199558399 has 2 divisors, whose sum is σ = 199199558400. Its totient is φ = 199199558398.
The previous prime is 199199558351. The next prime is 199199558407. The reversal of 199199558399 is 993855991991.
It is a strong prime.
It is an emirp because it is prime and its reverse (993855991991) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-199199558399 is a prime.
It is a super-2 number, since 2×1991995583992 (a number of 23 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (199199548399) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 99599779199 + 99599779200.
It is an arithmetic number, because the mean of its divisors is an integer number (99599779200).
Almost surely, 2199199558399 is an apocalyptic number.
199199558399 is a deficient number, since it is larger than the sum of its proper divisors (1).
199199558399 is an equidigital number, since it uses as much as digits as its factorization.
199199558399 is an evil number, because the sum of its binary digits is even.
The product of its digits is 318864600, while the sum is 77.
The spelling of 199199558399 in words is "one hundred ninety-nine billion, one hundred ninety-nine million, five hundred fifty-eight thousand, three hundred ninety-nine".
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