Base | Representation |
---|---|
bin | 101101010111001100110111… |
… | …100100001000010100101011 |
3 | 222011101122001002110001000022 |
4 | 231113030313210020110223 |
5 | 202122203211232202101 |
6 | 1544152000201231055 |
7 | 60010603005254234 |
oct | 5527146744102453 |
9 | 864348032401008 |
10 | 199506458084651 |
11 | 586292395144a3 |
12 | 1a46183119248b |
13 | 87424bc0a7693 |
14 | 373a2423b408b |
15 | 180e94a3cca1b |
hex | b5733790852b |
199506458084651 has 2 divisors, whose sum is σ = 199506458084652. Its totient is φ = 199506458084650.
The previous prime is 199506458084581. The next prime is 199506458084653. The reversal of 199506458084651 is 156480854605991.
199506458084651 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 199506458084651 - 234 = 199489278215467 is a prime.
Together with 199506458084653, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (199506458084653) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 99753229042325 + 99753229042326.
It is an arithmetic number, because the mean of its divisors is an integer number (99753229042326).
Almost surely, 2199506458084651 is an apocalyptic number.
199506458084651 is a deficient number, since it is larger than the sum of its proper divisors (1).
199506458084651 is an equidigital number, since it uses as much as digits as its factorization.
199506458084651 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 373248000, while the sum is 71.
The spelling of 199506458084651 in words is "one hundred ninety-nine trillion, five hundred six billion, four hundred fifty-eight million, eighty-four thousand, six hundred fifty-one".
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