Base | Representation |
---|---|
bin | 10010100101010001… |
… | …101101101110000011 |
3 | 1220111112121220021211 |
4 | 102211101231232003 |
5 | 311330401103124 |
6 | 13055520430551 |
7 | 1304306415055 |
oct | 224521555603 |
9 | 56445556254 |
10 | 19952753539 |
11 | 850989a064 |
12 | 3a4a178457 |
13 | 1b5c974954 |
14 | d73d078d5 |
15 | 7bba36e94 |
hex | 4a546db83 |
19952753539 has 2 divisors, whose sum is σ = 19952753540. Its totient is φ = 19952753538.
The previous prime is 19952753531. The next prime is 19952753573. The reversal of 19952753539 is 93535725991.
It is a weak prime.
It is an emirp because it is prime and its reverse (93535725991) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 19952753539 - 23 = 19952753531 is a prime.
It is a super-2 number, since 2×199527535392 (a number of 21 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (19952753531) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 9976376769 + 9976376770.
It is an arithmetic number, because the mean of its divisors is an integer number (9976376770).
Almost surely, 219952753539 is an apocalyptic number.
19952753539 is a deficient number, since it is larger than the sum of its proper divisors (1).
19952753539 is an equidigital number, since it uses as much as digits as its factorization.
19952753539 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 11481750, while the sum is 58.
The spelling of 19952753539 in words is "nineteen billion, nine hundred fifty-two million, seven hundred fifty-three thousand, five hundred thirty-nine".
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