Base | Representation |
---|---|
bin | 101101011000101111001011… |
… | …011000101111100111100101 |
3 | 222011202201111200210221222111 |
4 | 231120233023120233213211 |
5 | 202130420402414433244 |
6 | 1544312254514401021 |
7 | 60021330605202001 |
oct | 5530571330574745 |
9 | 864681450727874 |
10 | 199612017342949 |
11 | 58669a87a08642 |
12 | 1a47a190890171 |
13 | 874c442578273 |
14 | 37413b78b5701 |
15 | 18125776dee34 |
hex | b58bcb62f9e5 |
199612017342949 has 2 divisors, whose sum is σ = 199612017342950. Its totient is φ = 199612017342948.
The previous prime is 199612017342917. The next prime is 199612017343007. The reversal of 199612017342949 is 949243710216991.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 194476468212324 + 5135549130625 = 13945482^2 + 2266175^2 .
It is a cyclic number.
It is not a de Polignac number, because 199612017342949 - 25 = 199612017342917 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (199612017346949) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 99806008671474 + 99806008671475.
It is an arithmetic number, because the mean of its divisors is an integer number (99806008671475).
Almost surely, 2199612017342949 is an apocalyptic number.
It is an amenable number.
199612017342949 is a deficient number, since it is larger than the sum of its proper divisors (1).
199612017342949 is an equidigital number, since it uses as much as digits as its factorization.
199612017342949 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 52907904, while the sum is 67.
The spelling of 199612017342949 in words is "one hundred ninety-nine trillion, six hundred twelve billion, seventeen million, three hundred forty-two thousand, nine hundred forty-nine".
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