Base | Representation |
---|---|
bin | 10010100101111101… |
… | …000010101010011001 |
3 | 1220112022222221111112 |
4 | 102211331002222121 |
5 | 311341303032023 |
6 | 13101004110105 |
7 | 1304505101513 |
oct | 224575025231 |
9 | 56468887445 |
10 | 19964111513 |
11 | 8515247515 |
12 | 3a51b35335 |
13 | 1b62120648 |
14 | d75622bb3 |
15 | 7bca2c478 |
hex | 4a5f42a99 |
19964111513 has 2 divisors, whose sum is σ = 19964111514. Its totient is φ = 19964111512.
The previous prime is 19964111491. The next prime is 19964111539. The reversal of 19964111513 is 31511146991.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 11670913024 + 8293198489 = 108032^2 + 91067^2 .
It is an emirp because it is prime and its reverse (31511146991) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-19964111513 is a prime.
It is not a weakly prime, because it can be changed into another prime (19964111593) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 9982055756 + 9982055757.
It is an arithmetic number, because the mean of its divisors is an integer number (9982055757).
Almost surely, 219964111513 is an apocalyptic number.
It is an amenable number.
19964111513 is a deficient number, since it is larger than the sum of its proper divisors (1).
19964111513 is an equidigital number, since it uses as much as digits as its factorization.
19964111513 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 29160, while the sum is 41.
The spelling of 19964111513 in words is "nineteen billion, nine hundred sixty-four million, one hundred eleven thousand, five hundred thirteen".
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