19973433 has 4 divisors (see below), whose sum is σ = 26631248. Its totient is φ = 13315620.

The previous prime is 19973423. The next prime is 19973461. The reversal of 19973433 is 33437991.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 33437991 = 3 ⋅11145997.

It is not a de Polignac number, because 19973433 - 2²¹ = 17876281 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 19973391 and 19973400.

It is not an unprimeable number, because it can be changed into a prime (19973423) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3328903 + ... + 3328908.

It is an arithmetic number, because the mean of its divisors is an integer number (6657812).

Almost surely, 2^19973433 is an apocalyptic number.

It is an amenable number.

19973433 is a deficient number, since it is larger than the sum of its proper divisors (6657815).

19973433 is an equidigital number, since it uses as much as digits as its factorization.

19973433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6657814.

The product of its digits is 61236, while the sum is 39.

The square root of 19973433 is about 4469.1646870528. The cubic root of 19973433 is about 271.3215185141.

The spelling of 19973433 in words is "nineteen million, nine hundred seventy-three thousand, four hundred thirty-three".