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1998517483 is a prime number
BaseRepresentation
bin111011100011110…
…1111010011101011
312011021120012121001
41313013233103223
513043110024413
6530151055431
7100345055404
oct16707572353
95137505531
101998517483
11936124846
12479371577
1325b078631
1414d5d09ab
15ba6bd4dd
hex771ef4eb

1998517483 has 2 divisors, whose sum is σ = 1998517484. Its totient is φ = 1998517482.

The previous prime is 1998517463. The next prime is 1998517511. The reversal of 1998517483 is 3847158991.

It is a happy number.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 1998517483 - 213 = 1998509291 is a prime.

It is not a weakly prime, because it can be changed into another prime (1998517463) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 999258741 + 999258742.

It is an arithmetic number, because the mean of its divisors is an integer number (999258742).

Almost surely, 21998517483 is an apocalyptic number.

1998517483 is a deficient number, since it is larger than the sum of its proper divisors (1).

1998517483 is an equidigital number, since it uses as much as digits as its factorization.

1998517483 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 2177280, while the sum is 55.

The square root of 1998517483 is about 44704.7814333098. The cubic root of 1998517483 is about 1259.6096638805.

It can be divided in two parts, 1998517 and 483, that added together give a triangular number (1999000 = T1999).

The spelling of 1998517483 in words is "one billion, nine hundred ninety-eight million, five hundred seventeen thousand, four hundred eighty-three".