Base | Representation |
---|---|
bin | 10010100111100000… |
… | …000001101000011011 |
3 | 1220121010211020111211 |
4 | 102213200001220123 |
5 | 311414423401142 |
6 | 13103332203551 |
7 | 1305241462663 |
oct | 224740015033 |
9 | 56533736454 |
10 | 19990059547 |
11 | 852895a677 |
12 | 3a5a7695b7 |
13 | 1b67607203 |
14 | d78c591a3 |
15 | 7bee55917 |
hex | 4a7801a1b |
19990059547 has 2 divisors, whose sum is σ = 19990059548. Its totient is φ = 19990059546.
The previous prime is 19990059527. The next prime is 19990059563. The reversal of 19990059547 is 74595009991.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 19990059547 - 215 = 19990026779 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 19990059491 and 19990059500.
It is not a weakly prime, because it can be changed into another prime (19990059527) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 9995029773 + 9995029774.
It is an arithmetic number, because the mean of its divisors is an integer number (9995029774).
Almost surely, 219990059547 is an apocalyptic number.
19990059547 is a deficient number, since it is larger than the sum of its proper divisors (1).
19990059547 is an equidigital number, since it uses as much as digits as its factorization.
19990059547 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 4592700, while the sum is 58.
The spelling of 19990059547 in words is "nineteen billion, nine hundred ninety million, fifty-nine thousand, five hundred forty-seven".
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