Base | Representation |
---|---|
bin | 1011101000101101100… |
… | …0100000110011111101 |
3 | 201002222212012111001112 |
4 | 2322023120200303331 |
5 | 11233402140020433 |
6 | 231500323451405 |
7 | 20304611035211 |
oct | 2721330406375 |
9 | 632885174045 |
10 | 199906954493 |
11 | 7786429a794 |
12 | 328b0526b65 |
13 | 15b0ac71c6c |
14 | 99659c0941 |
15 | 53001e5348 |
hex | 2e8b620cfd |
199906954493 has 4 divisors (see below), whose sum is σ = 200510903328. Its totient is φ = 199303005660.
The previous prime is 199906954459. The next prime is 199906954561. The reversal of 199906954493 is 394459609991.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 199906954493 - 220 = 199905905917 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (199906954433) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 301973921 + ... + 301974582.
It is an arithmetic number, because the mean of its divisors is an integer number (50127725832).
Almost surely, 2199906954493 is an apocalyptic number.
It is an amenable number.
199906954493 is a deficient number, since it is larger than the sum of its proper divisors (603948835).
199906954493 is an equidigital number, since it uses as much as digits as its factorization.
199906954493 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 603948834.
The product of its (nonzero) digits is 85030560, while the sum is 68.
The spelling of 199906954493 in words is "one hundred ninety-nine billion, nine hundred six million, nine hundred fifty-four thousand, four hundred ninety-three".
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