Search a number
-
+
19992000797 = 97206103101
BaseRepresentation
bin10010100111100111…
…011011100100011101
31220121021110212101222
4102213213123210131
5311420423011142
613103441543125
71305264126416
oct224747334435
956537425358
1019992000797
118529a6610a
123a5b344aa5
131b67b36992
14d7920280d
157c01dabd2
hex4a79db91d

19992000797 has 4 divisors (see below), whose sum is σ = 20198103996. Its totient is φ = 19785897600.

The previous prime is 19992000767. The next prime is 19992000817. The reversal of 19992000797 is 79700029991.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 4074141241 + 15917859556 = 63829^2 + 126166^2 .

It is a cyclic number.

It is not a de Polignac number, because 19992000797 - 210 = 19991999773 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (19992000727) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 103051454 + ... + 103051647.

It is an arithmetic number, because the mean of its divisors is an integer number (5049525999).

Almost surely, 219992000797 is an apocalyptic number.

It is an amenable number.

19992000797 is a deficient number, since it is larger than the sum of its proper divisors (206103199).

19992000797 is an equidigital number, since it uses as much as digits as its factorization.

19992000797 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 206103198.

The product of its (nonzero) digits is 642978, while the sum is 53.

The spelling of 19992000797 in words is "nineteen billion, nine hundred ninety-two million, seven hundred ninety-seven", and thus it is an aban number.

Divisors: 1 97 206103101 19992000797