199920013 has 4 divisors (see below), whose sum is σ = 201861088. Its totient is φ = 197978940.

The previous prime is 199920001. The next prime is 199920031. The reversal of 199920013 is 310029991.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 310029991 = 311 ⋅996881.

It is a cyclic number.

It is not a de Polignac number, because 199920013 - 2⁵ = 199919981 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (199924013) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 970383 + ... + 970588.

It is an arithmetic number, because the mean of its divisors is an integer number (50465272).

Almost surely, 2^199920013 is an apocalyptic number.

It is an amenable number.

199920013 is a deficient number, since it is larger than the sum of its proper divisors (1941075).

199920013 is a wasteful number, since it uses less digits than its factorization.

199920013 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1941074.

The product of its (nonzero) digits is 4374, while the sum is 34.

The square root of 199920013 is about 14139.3073734183. The cubic root of 199920013 is about 584.7255761115.

The spelling of 199920013 in words is "one hundred ninety-nine million, nine hundred twenty thousand, thirteen".