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199954100413 is a prime number
BaseRepresentation
bin1011101000111000110…
…0010111000010111101
3201010010010220202002201
42322032030113002331
511234001222203123
6231505130151501
720306022544654
oct2721614270275
9633103822081
10199954100413
1177888971161
1232904282591
1315b1796b262
14996bd7419b
1553044095ad
hex2e8e3170bd

199954100413 has 2 divisors, whose sum is σ = 199954100414. Its totient is φ = 199954100412.

The previous prime is 199954100407. The next prime is 199954100429. The reversal of 199954100413 is 314001459991.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 187473412324 + 12480688089 = 432982^2 + 111717^2 .

It is an emirp because it is prime and its reverse (314001459991) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-199954100413 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (199954100473) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 99977050206 + 99977050207.

It is an arithmetic number, because the mean of its divisors is an integer number (99977050207).

Almost surely, 2199954100413 is an apocalyptic number.

It is an amenable number.

199954100413 is a deficient number, since it is larger than the sum of its proper divisors (1).

199954100413 is an equidigital number, since it uses as much as digits as its factorization.

199954100413 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 174960, while the sum is 46.

The spelling of 199954100413 in words is "one hundred ninety-nine billion, nine hundred fifty-four million, one hundred thousand, four hundred thirteen".