Base | Representation |
---|---|
bin | 1011101000111000110… |
… | …0010111000010111101 |
3 | 201010010010220202002201 |
4 | 2322032030113002331 |
5 | 11234001222203123 |
6 | 231505130151501 |
7 | 20306022544654 |
oct | 2721614270275 |
9 | 633103822081 |
10 | 199954100413 |
11 | 77888971161 |
12 | 32904282591 |
13 | 15b1796b262 |
14 | 996bd7419b |
15 | 53044095ad |
hex | 2e8e3170bd |
199954100413 has 2 divisors, whose sum is σ = 199954100414. Its totient is φ = 199954100412.
The previous prime is 199954100407. The next prime is 199954100429. The reversal of 199954100413 is 314001459991.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 187473412324 + 12480688089 = 432982^2 + 111717^2 .
It is an emirp because it is prime and its reverse (314001459991) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-199954100413 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (199954100473) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 99977050206 + 99977050207.
It is an arithmetic number, because the mean of its divisors is an integer number (99977050207).
Almost surely, 2199954100413 is an apocalyptic number.
It is an amenable number.
199954100413 is a deficient number, since it is larger than the sum of its proper divisors (1).
199954100413 is an equidigital number, since it uses as much as digits as its factorization.
199954100413 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 174960, while the sum is 46.
The spelling of 199954100413 in words is "one hundred ninety-nine billion, nine hundred fifty-four million, one hundred thousand, four hundred thirteen".
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