1999940119813 has 4 divisors (see below), whose sum is σ = 2000088288000. Its totient is φ = 1999791951628.

The previous prime is 1999940119777. The next prime is 1999940119823. The reversal of 1999940119813 is 3189110499991.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1999940119813 - 2¹³ = 1999940111621 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1999940119823) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 74063845 + ... + 74090842.

It is an arithmetic number, because the mean of its divisors is an integer number (500022072000).

Almost surely, 2^{1999940119813} is an apocalyptic number.

It is an amenable number.

1999940119813 is a deficient number, since it is larger than the sum of its proper divisors (148168187).

1999940119813 is a wasteful number, since it uses less digits than its factorization.

1999940119813 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 148168186.

The product of its (nonzero) digits is 5668704, while the sum is 64.

The spelling of 1999940119813 in words is "one trillion, nine hundred ninety-nine billion, nine hundred forty million, one hundred nineteen thousand, eight hundred thirteen".