199999943113147 has 2 divisors, whose sum is σ = 199999943113148. Its totient is φ = 199999943113146.

The previous prime is 199999943113141. The next prime is 199999943113153. The reversal of 199999943113147 is 741311349999991.

It is a balanced prime because it is at equal distance from previous prime (199999943113141) and next prime (199999943113153).

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-199999943113147 is a prime.

It is a super-2 number, since 2×199999943113147² (a number of 29 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (199999943113141) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 99999971556573 + 99999971556574.

It is an arithmetic number, because the mean of its divisors is an integer number (99999971556574).

Almost surely, 2^{199999943113147} is an apocalyptic number.

199999943113147 is a deficient number, since it is larger than the sum of its proper divisors (1).

199999943113147 is an equidigital number, since it uses as much as digits as its factorization.

199999943113147 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 535692528, while the sum is 79.

The spelling of 199999943113147 in words is "one hundred ninety-nine trillion, nine hundred ninety-nine billion, nine hundred forty-three million, one hundred thirteen thousand, one hundred forty-seven".