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20000000000401 = 168791184904319
BaseRepresentation
bin1001000110000100111001…
…11001010100000110010001
32121210222111101110112012121
410203002130321110012101
510110140000000003101
6110311512334054241
74132644434023021
oct443023471240621
977728441415177
1020000000000401
116410a52668373
1222b017364a381
13b20cb82b3c85
144d201025ba81
1524a3a4d860a1
hex12309ce54191

20000000000401 has 4 divisors (see below), whose sum is σ = 20001184921600. Its totient is φ = 19998815079204.

The previous prime is 20000000000399. The next prime is 20000000000443. The reversal of 20000000000401 is 10400000000002.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 20000000000401 - 21 = 20000000000399 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (20000003000401) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 592435281 + ... + 592469038.

It is an arithmetic number, because the mean of its divisors is an integer number (5000296230400).

Almost surely, 220000000000401 is an apocalyptic number.

It is an amenable number.

20000000000401 is a deficient number, since it is larger than the sum of its proper divisors (1184921199).

20000000000401 is a wasteful number, since it uses less digits than its factorization.

20000000000401 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1184921198.

The product of its (nonzero) digits is 8, while the sum is 7.

Adding to 20000000000401 its reverse (10400000000002), we get a palindrome (30400000000403).

The spelling of 20000000000401 in words is "twenty trillion, four hundred one", and thus it is an aban number.

Divisors: 1 16879 1184904319 20000000000401