200000000051 has 4 divisors (see below), whose sum is σ = 200193987504. Its totient is φ = 199806012600.

The previous prime is 200000000041. The next prime is 200000000077. The reversal of 200000000051 is 150000000002.

200000000051 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 150000000002 = 2 ⋅75000000001.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-200000000051 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 199999999957 and 200000000038.

It is not an unprimeable number, because it can be changed into a prime (200000000041) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 96992180 + ... + 96994241.

It is an arithmetic number, because the mean of its divisors is an integer number (50048496876).

Almost surely, 2^200000000051 is an apocalyptic number.

200000000051 is a deficient number, since it is larger than the sum of its proper divisors (193987453).

200000000051 is a wasteful number, since it uses less digits than its factorization.

200000000051 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 193987452.

The product of its (nonzero) digits is 10, while the sum is 8.

Adding to 200000000051 its reverse (150000000002), we get a palindrome (350000000053).

The spelling of 200000000051 in words is "two hundred billion, fifty-one", and thus it is an aban number.