200000313011 has 4 divisors (see below), whose sum is σ = 200041837512. Its totient is φ = 199958788512.

The previous prime is 200000313001. The next prime is 200000313017. The reversal of 200000313011 is 110313000002.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-200000313011 is a prime.

It is a super-2 number, since 2×200000313011² (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 200000312983 and 200000313001.

It is not an unprimeable number, because it can be changed into a prime (200000313017) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 20755025 + ... + 20764658.

It is an arithmetic number, because the mean of its divisors is an integer number (50010459378).

Almost surely, 2^200000313011 is an apocalyptic number.

200000313011 is a deficient number, since it is larger than the sum of its proper divisors (41524501).

200000313011 is an equidigital number, since it uses as much as digits as its factorization.

200000313011 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 41524500.

The product of its (nonzero) digits is 18, while the sum is 11.

Adding to 200000313011 its reverse (110313000002), we get a palindrome (310313313013).

The spelling of 200000313011 in words is "two hundred billion, three hundred thirteen thousand, eleven".