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2000012017 is a prime number
BaseRepresentation
bin111011100110101…
…1100001011110001
312011101101010201011
41313031130023301
513044000341032
6530243110521
7100363551553
oct16715341361
95141333634
102000012017
11936a556a3
12479972441
1325b47c983
1414d89d4d3
15ba8b6247
hex7735c2f1

2000012017 has 2 divisors, whose sum is σ = 2000012018. Its totient is φ = 2000012016.

The previous prime is 2000011987. The next prime is 2000012051. The reversal of 2000012017 is 7102100002.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1911350961 + 88661056 = 43719^2 + 9416^2 .

It is a cyclic number.

It is not a de Polignac number, because 2000012017 - 215 = 1999979249 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 2000011988 and 2000012006.

It is not a weakly prime, because it can be changed into another prime (2000072017) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1000006008 + 1000006009.

It is an arithmetic number, because the mean of its divisors is an integer number (1000006009).

Almost surely, 22000012017 is an apocalyptic number.

It is an amenable number.

2000012017 is a deficient number, since it is larger than the sum of its proper divisors (1).

2000012017 is an equidigital number, since it uses as much as digits as its factorization.

2000012017 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 28, while the sum is 13.

The square root of 2000012017 is about 44721.4939039384. The cubic root of 2000012017 is about 1259.9235733017.

Adding to 2000012017 its reverse (7102100002), we get a palindrome (9102112019).

The spelling of 2000012017 in words is "two billion, twelve thousand, seventeen".