200001230000041 has 4 divisors (see below), whose sum is σ = 200063169064900. Its totient is φ = 199939290935184.

The previous prime is 200001230000027. The next prime is 200001230000101. The reversal of 200001230000041 is 140000032100002.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 80690174838441 + 119311055161600 = 8982771^2 + 10922960^2 .

It is a cyclic number.

It is not a de Polignac number, because 200001230000041 - 2¹¹ = 200001229997993 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 200001229999976 and 200001230000030.

It is not an unprimeable number, because it can be changed into a prime (200001230000021) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 30969527586 + ... + 30969534043.

It is an arithmetic number, because the mean of its divisors is an integer number (50015792266225).

Almost surely, 2^{200001230000041} is an apocalyptic number.

It is an amenable number.

200001230000041 is a deficient number, since it is larger than the sum of its proper divisors (61939064859).

200001230000041 is an equidigital number, since it uses as much as digits as its factorization.

200001230000041 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 61939064858.

The product of its (nonzero) digits is 48, while the sum is 13.

Adding to 200001230000041 its reverse (140000032100002), we get a palindrome (340001262100043).

The spelling of 200001230000041 in words is "two hundred trillion, one billion, two hundred thirty million, forty-one", and thus it is an aban number.