Base | Representation |
---|---|
bin | 101101011110011010011010… |
… | …000010011010101100100001 |
3 | 222020011000012110010102020121 |
4 | 231132122122002122230201 |
5 | 202203313130021233213 |
6 | 1545211355334040241 |
7 | 60061445533223311 |
oct | 5536323202325441 |
9 | 866130173112217 |
10 | 200002031430433 |
11 | 587aa426778081 |
12 | 1a5218977a9081 |
13 | 877a1590bc31b |
14 | 3756215741441 |
15 | 181c7a25ae88d |
hex | b5e69a09ab21 |
200002031430433 has 8 divisors (see below), whose sum is σ = 202331028443400. Its totient is φ = 197674851821568.
The previous prime is 200002031430431. The next prime is 200002031430479. The reversal of 200002031430433 is 334034130200002.
It can be written as a sum of positive squares in 4 ways, for example, as 49214265722944 + 150787765707489 = 7015288^2 + 12279567^2 .
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 200002031430433 - 21 = 200002031430431 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 200002031430398 and 200002031430407.
It is not an unprimeable number, because it can be changed into a prime (200002031430431) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 454129648 + ... + 454569841.
It is an arithmetic number, because the mean of its divisors is an integer number (25291378555425).
Almost surely, 2200002031430433 is an apocalyptic number.
It is an amenable number.
200002031430433 is a deficient number, since it is larger than the sum of its proper divisors (2328997012967).
200002031430433 is an equidigital number, since it uses as much as digits as its factorization.
200002031430433 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 908702051.
The product of its (nonzero) digits is 5184, while the sum is 25.
Adding to 200002031430433 its reverse (334034130200002), we get a palindrome (534036161630435).
The spelling of 200002031430433 in words is "two hundred trillion, two billion, thirty-one million, four hundred thirty thousand, four hundred thirty-three".
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