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200004041411 = 434651256777
BaseRepresentation
bin1011101001000100101…
…0110111101011000011
3201010020121220000021022
42322101022313223003
511234102013311121
6231514112420055
720310200205356
oct2722112675303
9633217800238
10200004041411
1177904081609
1232918b4762b
1315b25105845
14997485429d
1553089c1aab
hex2e912b7ac3

200004041411 has 4 divisors (see below), whose sum is σ = 204655298232. Its totient is φ = 195352784592.

The previous prime is 200004041399. The next prime is 200004041437. The reversal of 200004041411 is 114140400002.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 200004041411 - 218 = 200003779267 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 200004041411.

It is not an unprimeable number, because it can be changed into a prime (200004041441) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2325628346 + ... + 2325628431.

It is an arithmetic number, because the mean of its divisors is an integer number (51163824558).

Almost surely, 2200004041411 is an apocalyptic number.

200004041411 is a deficient number, since it is larger than the sum of its proper divisors (4651256821).

200004041411 is an equidigital number, since it uses as much as digits as its factorization.

200004041411 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4651256820.

The product of its (nonzero) digits is 128, while the sum is 17.

Adding to 200004041411 its reverse (114140400002), we get a palindrome (314144441413).

The spelling of 200004041411 in words is "two hundred billion, four million, forty-one thousand, four hundred eleven".

Divisors: 1 43 4651256777 200004041411