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2000044945 = 5400008989
BaseRepresentation
bin111011100110110…
…0100001110010001
312011101102210212201
41313031210032101
513044002414240
6530243523201
7100364046553
oct16715441621
95141383781
102000044945
11936a78408
12479989501
1325b491962
1414d8ab4d3
15ba8c0d9a
hex77364391

2000044945 has 4 divisors (see below), whose sum is σ = 2400053940. Its totient is φ = 1600035952.

The previous prime is 2000044913. The next prime is 2000044957. The reversal of 2000044945 is 5494400002.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 1471412881 + 528632064 = 38359^2 + 22992^2 .

It is a cyclic number.

It is not a de Polignac number, because 2000044945 - 25 = 2000044913 is a prime.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 200004490 + ... + 200004499.

It is an arithmetic number, because the mean of its divisors is an integer number (600013485).

Almost surely, 22000044945 is an apocalyptic number.

It is an amenable number.

2000044945 is a deficient number, since it is larger than the sum of its proper divisors (400008995).

2000044945 is an equidigital number, since it uses as much as digits as its factorization.

2000044945 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 400008994.

The product of its (nonzero) digits is 5760, while the sum is 28.

The square root of 2000044945 is about 44721.8620475490. The cubic root of 2000044945 is about 1259.9304876828.

Adding to 2000044945 its reverse (5494400002), we get a palindrome (7494444947).

The spelling of 2000044945 in words is "two billion, forty-four thousand, nine hundred forty-five".

Divisors: 1 5 400008989 2000044945