Base | Representation |
---|---|
bin | 1011101001000101000… |
… | …0011100110001110101 |
3 | 201010020201122022201121 |
4 | 2322101100130301311 |
5 | 11234102402112432 |
6 | 231514204023541 |
7 | 20310215506666 |
oct | 2722120346165 |
9 | 633221568647 |
10 | 200005504117 |
11 | 77904990561 |
12 | 32919531bb1 |
13 | 15b254c8553 |
14 | 9974b1536d |
15 | 5308bb0197 |
hex | 2e9141cc75 |
200005504117 has 2 divisors, whose sum is σ = 200005504118. Its totient is φ = 200005504116.
The previous prime is 200005504091. The next prime is 200005504147. The reversal of 200005504117 is 711405500002.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 189783080881 + 10222423236 = 435641^2 + 101106^2 .
It is a cyclic number.
It is not a de Polignac number, because 200005504117 - 215 = 200005471349 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 200005504091 and 200005504100.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (200005504147) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100002752058 + 100002752059.
It is an arithmetic number, because the mean of its divisors is an integer number (100002752059).
Almost surely, 2200005504117 is an apocalyptic number.
It is an amenable number.
200005504117 is a deficient number, since it is larger than the sum of its proper divisors (1).
200005504117 is an equidigital number, since it uses as much as digits as its factorization.
200005504117 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1400, while the sum is 25.
The spelling of 200005504117 in words is "two hundred billion, five million, five hundred four thousand, one hundred seventeen".
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