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20001000211 = 81792445409
BaseRepresentation
bin10010101000001001…
…110000101100010011
31220121220102002021121
4102220021300230103
5311430224001321
613104402503111
71305433460653
oct225011605423
956556362247
1020001000211
118534052545
123a62364a97
131b69967c8a
14d7a4a6363
157c0db7441
hex4a8270b13

20001000211 has 4 divisors (see below), whose sum is σ = 20003453800. Its totient is φ = 19998546624.

The previous prime is 20001000181. The next prime is 20001000233. The reversal of 20001000211 is 11200010002.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 20001000211 - 27 = 20001000083 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 20001000194 and 20001000203.

It is not an unprimeable number, because it can be changed into a prime (20001000251) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1214526 + ... + 1230883.

It is an arithmetic number, because the mean of its divisors is an integer number (5000863450).

Almost surely, 220001000211 is an apocalyptic number.

20001000211 is a deficient number, since it is larger than the sum of its proper divisors (2453589).

20001000211 is an equidigital number, since it uses as much as digits as its factorization.

20001000211 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2453588.

The product of its (nonzero) digits is 4, while the sum is 7.

Adding to 20001000211 its reverse (11200010002), we get a palindrome (31201010213).

It can be divided in two parts, 200010002 and 11, that multiplied together give a palindrome (2200110022).

The spelling of 20001000211 in words is "twenty billion, one million, two hundred eleven", and thus it is an aban number.

Divisors: 1 8179 2445409 20001000211