20001102019933 has 2 divisors, whose sum is σ = 20001102019934. Its totient is φ = 20001102019932.

The previous prime is 20001102019901. The next prime is 20001102020047. The reversal of 20001102019933 is 33991020110002.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 19630242943609 + 370859076324 = 4430603^2 + 608982^2 .

It is a cyclic number.

It is not a de Polignac number, because 20001102019933 - 2⁵ = 20001102019901 is a prime.

It is a super-4 number, since 4×20001102019933⁴ (a number of 54 digits) contains 4444 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 20001102019895 and 20001102019904.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (20001102419933) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10000551009966 + 10000551009967.

It is an arithmetic number, because the mean of its divisors is an integer number (10000551009967).

Almost surely, 2^{20001102019933} is an apocalyptic number.

It is an amenable number.

20001102019933 is a deficient number, since it is larger than the sum of its proper divisors (1).

20001102019933 is an equidigital number, since it uses as much as digits as its factorization.

20001102019933 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2916, while the sum is 31.

Adding to 20001102019933 its reverse (33991020110002), we get a palindrome (53992122129935).

The spelling of 20001102019933 in words is "twenty trillion, one billion, one hundred two million, nineteen thousand, nine hundred thirty-three".