Base | Representation |
---|---|
bin | 101101011110100010110001… |
… | …110111010111101011000111 |
3 | 222020011212101221211002002021 |
4 | 231132202301313113223013 |
5 | 202203440032401402442 |
6 | 1545215443350224011 |
7 | 60062214362312326 |
oct | 5536426167275307 |
9 | 866155357732067 |
10 | 200011021122247 |
11 | 5880321a168645 |
12 | 1a523586355007 |
13 | 877ac5c6a06aa |
14 | 37568296320bd |
15 | 181cb2b901e67 |
hex | b5e8b1dd7ac7 |
200011021122247 has 2 divisors, whose sum is σ = 200011021122248. Its totient is φ = 200011021122246.
The previous prime is 200011021122113. The next prime is 200011021122277. The reversal of 200011021122247 is 742221120110002.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 200011021122247 - 239 = 199461265308359 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (200011021122277) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100005510561123 + 100005510561124.
It is an arithmetic number, because the mean of its divisors is an integer number (100005510561124).
Almost surely, 2200011021122247 is an apocalyptic number.
200011021122247 is a deficient number, since it is larger than the sum of its proper divisors (1).
200011021122247 is an equidigital number, since it uses as much as digits as its factorization.
200011021122247 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 896, while the sum is 25.
Adding to 200011021122247 its reverse (742221120110002), we get a palindrome (942232141232249).
The spelling of 200011021122247 in words is "two hundred trillion, eleven billion, twenty-one million, one hundred twenty-two thousand, two hundred forty-seven".
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