2000112113 has 4 divisors (see below), whose sum is σ = 2000367348. Its totient is φ = 1999856880.

The previous prime is 2000112077. The next prime is 2000112139. The reversal of 2000112113 is 3112110002.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 1512276544 + 487835569 = 38888^2 + 22087^2 .

It is a cyclic number.

It is not a de Polignac number, because 2000112113 - 2¹⁴ = 2000095729 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 2000112094 and 2000112103.

It is not an unprimeable number, because it can be changed into a prime (2000112193) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 115478 + ... + 131663.

It is an arithmetic number, because the mean of its divisors is an integer number (500091837).

Almost surely, 2^2000112113 is an apocalyptic number.

It is an amenable number.

2000112113 is a deficient number, since it is larger than the sum of its proper divisors (255235).

2000112113 is an equidigital number, since it uses as much as digits as its factorization.

2000112113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 255234.

The product of its (nonzero) digits is 12, while the sum is 11.

The square root of 2000112113 is about 44722.6129938759. The cubic root of 2000112113 is about 1259.9445917098.

Adding to 2000112113 its reverse (3112110002), we get a palindrome (5112222115).

The spelling of 2000112113 in words is "two billion, one hundred twelve thousand, one hundred thirteen".