Base | Representation |
---|---|
bin | 1011101001000110011… |
… | …0100100100011001101 |
3 | 201010021010112221110101 |
4 | 2322101212210203031 |
5 | 11234110343144432 |
6 | 231514532211101 |
7 | 20310316011463 |
oct | 2722146444315 |
9 | 633233487411 |
10 | 200011303117 |
11 | 7790819141a |
12 | 3291b469a91 |
13 | 15b26778c02 |
14 | 99757c4833 |
15 | 53094584e7 |
hex | 2e919a48cd |
200011303117 has 2 divisors, whose sum is σ = 200011303118. Its totient is φ = 200011303116.
The previous prime is 200011302989. The next prime is 200011303187. The reversal of 200011303117 is 711303110002.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 190880736201 + 9130566916 = 436899^2 + 95554^2 .
It is a cyclic number.
It is not a de Polignac number, because 200011303117 - 27 = 200011302989 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 200011303094 and 200011303103.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (200011303187) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100005651558 + 100005651559.
It is an arithmetic number, because the mean of its divisors is an integer number (100005651559).
Almost surely, 2200011303117 is an apocalyptic number.
It is an amenable number.
200011303117 is a deficient number, since it is larger than the sum of its proper divisors (1).
200011303117 is an equidigital number, since it uses as much as digits as its factorization.
200011303117 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 126, while the sum is 19.
Adding to 200011303117 its reverse (711303110002), we get a palindrome (911314413119).
The spelling of 200011303117 in words is "two hundred billion, eleven million, three hundred three thousand, one hundred seventeen".
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