Search a number
-
+
20001200021113 is a prime number
BaseRepresentation
bin1001000110000111001000…
…11011000001111001111001
32121211002121000111220011011
410203003210123001321321
510110144424201133423
6110312231402433521
74133016245025463
oct443034433017171
977732530456134
1020001200021113
116411508a88723
1222b04495028a1
13b21149ab49bc
144d20c5795133
1524a4253c7b0d
hex1230e46c1e79

20001200021113 has 2 divisors, whose sum is σ = 20001200021114. Its totient is φ = 20001200021112.

The previous prime is 20001200021063. The next prime is 20001200021141. The reversal of 20001200021113 is 31112000210002.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 10062262819449 + 9938937201664 = 3172107^2 + 3152608^2 .

It is a cyclic number.

It is not a de Polignac number, because 20001200021113 - 237 = 19863761067641 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 20001200021093 and 20001200021102.

It is not a weakly prime, because it can be changed into another prime (20001200021213) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10000600010556 + 10000600010557.

It is an arithmetic number, because the mean of its divisors is an integer number (10000600010557).

Almost surely, 220001200021113 is an apocalyptic number.

It is an amenable number.

20001200021113 is a deficient number, since it is larger than the sum of its proper divisors (1).

20001200021113 is an equidigital number, since it uses as much as digits as its factorization.

20001200021113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 24, while the sum is 13.

Adding to 20001200021113 its reverse (31112000210002), we get a palindrome (51113200231115).

The spelling of 20001200021113 in words is "twenty trillion, one billion, two hundred million, twenty-one thousand, one hundred thirteen".