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200012312131 is a prime number
BaseRepresentation
bin1011101001000110101…
…0011010111001000011
3201010021012110012120021
42322101222122321003
511234111122442011
6231515005554311
720310330413302
oct2722152327103
9633235405507
10200012312131
1177908810515
123291b875997
1315b26a40268
1499759a8439
1553095a7471
hex2e91a9ae43

200012312131 has 2 divisors, whose sum is σ = 200012312132. Its totient is φ = 200012312130.

The previous prime is 200012312099. The next prime is 200012312141. The reversal of 200012312131 is 131213210002.

200012312131 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 200012312131 - 25 = 200012312099 is a prime.

It is a super-2 number, since 2×2000123121312 (a number of 23 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (200012312141) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100006156065 + 100006156066.

It is an arithmetic number, because the mean of its divisors is an integer number (100006156066).

Almost surely, 2200012312131 is an apocalyptic number.

200012312131 is a deficient number, since it is larger than the sum of its proper divisors (1).

200012312131 is an equidigital number, since it uses as much as digits as its factorization.

200012312131 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 72, while the sum is 16.

Adding to 200012312131 its reverse (131213210002), we get a palindrome (331225522133).

The spelling of 200012312131 in words is "two hundred billion, twelve million, three hundred twelve thousand, one hundred thirty-one".