Base | Representation |
---|---|
bin | 101101011110100100000000… |
… | …101101110010111000001111 |
3 | 222020011222211011001212002021 |
4 | 231132210000231302320033 |
5 | 202204000240031343203 |
6 | 1545220222524311011 |
7 | 60062262224556544 |
oct | 5536440055627017 |
9 | 866158734055067 |
10 | 200012344012303 |
11 | 5880383897a509 |
12 | 1a5238953a2467 |
13 | 877b110791384 |
14 | 37569131d0bcb |
15 | 181cba7b145bd |
hex | b5e900b72e0f |
200012344012303 has 2 divisors, whose sum is σ = 200012344012304. Its totient is φ = 200012344012302.
The previous prime is 200012344012253. The next prime is 200012344012367. The reversal of 200012344012303 is 303210443210002.
200012344012303 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 200012344012303 - 29 = 200012344011791 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (200012344012603) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100006172006151 + 100006172006152.
It is an arithmetic number, because the mean of its divisors is an integer number (100006172006152).
Almost surely, 2200012344012303 is an apocalyptic number.
200012344012303 is a deficient number, since it is larger than the sum of its proper divisors (1).
200012344012303 is an equidigital number, since it uses as much as digits as its factorization.
200012344012303 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3456, while the sum is 25.
Adding to 200012344012303 its reverse (303210443210002), we get a palindrome (503222787222305).
The spelling of 200012344012303 in words is "two hundred trillion, twelve billion, three hundred forty-four million, twelve thousand, three hundred three".
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