Base | Representation |
---|---|
bin | 101101011110100100000100… |
… | …110110011111100010000111 |
3 | 222020011222222222122011210021 |
4 | 231132210010312133202013 |
5 | 202204000410312314343 |
6 | 1545220233443440011 |
7 | 60062264026426603 |
oct | 5536440466374207 |
9 | 866158888564707 |
10 | 200012413401223 |
11 | 58803874063425 |
12 | 1a5238b4686007 |
13 | 877b121c779c7 |
14 | 375691c4d4503 |
15 | 181cbadc6e0ed |
hex | b5e904d9f887 |
200012413401223 has 2 divisors, whose sum is σ = 200012413401224. Its totient is φ = 200012413401222.
The previous prime is 200012413401187. The next prime is 200012413401301. The reversal of 200012413401223 is 322104314210002.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 200012413401223 - 29 = 200012413400711 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (200012413401323) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100006206700611 + 100006206700612.
It is an arithmetic number, because the mean of its divisors is an integer number (100006206700612).
Almost surely, 2200012413401223 is an apocalyptic number.
200012413401223 is a deficient number, since it is larger than the sum of its proper divisors (1).
200012413401223 is an equidigital number, since it uses as much as digits as its factorization.
200012413401223 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2304, while the sum is 25.
Adding to 200012413401223 its reverse (322104314210002), we get a palindrome (522116727611225).
The spelling of 200012413401223 in words is "two hundred trillion, twelve billion, four hundred thirteen million, four hundred one thousand, two hundred twenty-three".
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